Karina has an 8 1/2inch by 11inch sheet of paper.She wants to leave a 3/4 inch margin on all 4 sides. What are the dimensions of the remaining area.
see previous post.
And geez, have a little patience...
8 1/2 - 1 1/2 = ?
11 - 1 1/2 = ?
To find the dimensions of the remaining area, we need to subtract the measurements of the margins from the measurements of the original sheet.
Given:
Width of the original sheet = 8 1/2 inches
Height of the original sheet = 11 inches
Margin on all four sides = 3/4 inch
To find the width of the remaining area, we subtract twice the margin from the original width:
Remaining Width = Original Width - (2 × Margin)
Remaining Width = 8 1/2 inches - (2 × 3/4 inch)
To subtract fractions, we need a common denominator. The least common multiple (LCM) of 2 and 4 is 4.
Remaining Width = 8 1/2 inches - (2 × (3/4) inch)
Remaining Width = 8 1/2 inches - (2 × (3/4) inch)
Remaining Width = 8 1/2 inches - (2 × 3/4 inch)
Remaining Width = 8 1/2 inches - (6/4 inch)
Remaining Width = 8 1/2 inches - (3/2 inch)
Now let's convert 8 1/2 inches to a fraction:
8 1/2 inches = 17/2 inches
Substituting the values into the equation:
Remaining Width = 17/2 inches - (3/2 inch)
Remaining Width = (17 - 3)/2 inches
Remaining Width = 14/2 inches
Remaining Width = 7 inches
So, the width of the remaining area is 7 inches.
Similarly, to find the height of the remaining area, we subtract twice the margin from the original height:
Remaining Height = Original Height - (2 × Margin)
Remaining Height = 11 inches - (2 × 3/4 inch)
Again, let's convert 11 inches to a fraction:
Remaining Height = 11 inches - (2 × (3/4) inch)
Remaining Height = (11/1) inches - (6/4) inches
Substituting the values into the equation:
Remaining Height = (11 - 6)/1 inches
Remaining Height = 5/1 inches
Remaining Height = 5 inches
Therefore, the dimensions of the remaining area are:
Width = 7 inches
Height = 5 inches