A particle is at x=+5m at t=0, x=-7m at t=6s and x=+2m at t=10s. Find the average velocity of the particle during the intervals.
(a) t=0 and t=6s (b) t=6s to t=10s (c) t=0 to t=10s
Average velocity is total displacement over total time.
For example in a) We went from +5 to -7 so displacement is -12. Time was 6 seconds. Ave vel = -12/6.
so wat is the exact answer to the answer?
To find the average velocity of a particle during an interval, you need to calculate the displacement divided by the elapsed time.
(a) t=0 and t=6s:
To find the displacement during this interval, subtract the initial position from the final position: -7m - 5m = -12m.
The elapsed time is given as 6s - 0s = 6s.
Average velocity = displacement / elapsed time = -12m / 6s = -2 m/s.
(b) t=6s to t=10s:
To find the displacement during this interval, subtract the initial position from the final position: +2m - (-7m) = 9m.
The elapsed time is given as 10s - 6s = 4s.
Average velocity = displacement / elapsed time = 9m / 4s = 2.25 m/s.
(c) t=0 to t=10s:
To find the displacement during this interval, subtract the initial position from the final position: +2m - 5m = -3m.
The elapsed time is given as 10s - 0s = 10s.
Average velocity = displacement / elapsed time = -3m / 10s = -0.3 m/s.
So, the average velocities during the intervals are:
(a) -2 m/s
(b) 2.25 m/s
(c) -0.3 m/s.