A ball is thrown vertically upward with a velocity of 30m/s. Determine the maximum height reached
gravity decelerates the ball
time to peak is ... 30 / 9.8
the velocity at peak is zero, so the average velocity is ... (30 + 0) / 2
peak height is average velocity,
multiplied by time
No answer
To determine the maximum height reached by the ball, we can use the equation of motion for vertical motion.
The equation that relates the final velocity (v), initial velocity (u), acceleration (a), and displacement (s) is:
v^2 = u^2 + 2as
In this case, the ball is thrown vertically upward, so the initial velocity (u) is +30 m/s (positive because it is in the upward direction), and the final velocity (v) will be 0 m/s at the maximum height. Acceleration (a) is equal to the acceleration due to gravity, which is -9.8 m/s^2 (negative because it acts in the opposite direction of the initial velocity). We need to find the displacement (s), which will be the maximum height reached by the ball.
Plugging in the values into the equation, we get:
0 = (30)^2 + 2 * (-9.8) * s
0 = 900 - 19.6s
19.6s = 900
s = 900 / 19.6
s ≈ 45.92 m
Therefore, the maximum height reached by the ball is approximately 45.92 meters.