The scale drawing of a swimming pool measures 2 inches by 3 inches. On the drawing .25 inches = 3 feet. What are the actual dimensions of the pool?

.25" : 3' = 1":12'

so,

2"x3" = 24'x36' =

It would be 24 feet x 36 feet.

Scale: .25 inches = 6 feet

If the actual length is 18 feet, what is the drawing length?

To find the actual dimensions of the pool, we need to convert the measurements on the scale drawing into real-world measurements using the given scale.

Let's start with the width of the pool. It is represented by 2 inches on the scale drawing. According to the scale, 0.25 inches on the drawing corresponds to 3 feet in reality. So, we can set up a proportion to find the width:

(2 inches) / (0.25 inches) = (x feet) / (3 feet)

Cross multiplying, we get:

2 * 3 = 0.25 * x

6 = 0.25x

To solve for x, divide both sides of the equation by 0.25:

6 / 0.25 = x

x = 24

So, the width of the pool is 24 feet.

Similarly, we can find the length of the pool using the given scale. The length is represented by 3 inches on the scale drawing. Using the same proportion as before, we have:

(3 inches) / (0.25 inches) = (x feet) / (3 feet)

Cross multiplying:

3 * 3 = 0.25 * x

9 = 0.25x

Dividing both sides by 0.25:

9 / 0.25 = x

x = 36

Therefore, the length of the pool is 36 feet.

In conclusion, the actual dimensions of the pool are 24 feet by 36 feet.