Question

Please help..

How to answer if..
2log8/6 + 2^2log3 - 2log12

Thank you so much

Answer 1

using these log rules:

log(ab) = loga + logb
log(a/b) = loga - logb
log( a^n) = nloga

Rewrite 2log8/6 + 2^2log3 - 2log12
as
log(64/36) + 4log3 - log144
= log(64/36) + log81 - log144
= log ( (64/36)(81)/144)
= log 1
= 0