Given: 3H2(g) + N2(g) 2NH3(g)
If the reaction starts with 0.500 mol of H2, how many atoms of hydrogen in the compound NH3 would you expect to make?
To determine the number of atoms of hydrogen in the compound NH3, we first need to find out how many moles of NH3 are produced from 0.500 mol of H2.
From the balanced equation: 3H2(g) + N2(g) -> 2NH3(g)
We can see that for every 3 moles of H2, we produce 2 moles of NH3. Therefore, we need to calculate the number of moles of NH3 produced:
(Number of moles of NH3) = (Number of moles of H2) * (Ratio of moles of NH3 to moles of H2)
Number of moles of NH3 = 0.500 mol H2 * (2 mol NH3 / 3 mol H2)
Number of moles of NH3 = 0.333 mol NH3
Now that we know the number of moles of NH3, we can calculate the number of molecules of NH3:
(Number of molecules of NH3) = (Number of moles of NH3) * (Avogadro's number)
Number of molecules of NH3 = 0.333 mol NH3 * (6.022 x 10^23 molecules/mol)
Number of molecules of NH3 = 2.004 x 10^23 molecules NH3
Finally, we can determine the number of atoms of hydrogen in the compound NH3. Since there are 3 hydrogen atoms in each NH3 molecule:
(Number of atoms of hydrogen) = (Number of molecules of NH3) * (Number of hydrogen atoms per molecule)
Number of atoms of hydrogen = 2.004 x 10^23 molecules NH3 * 3 (hydrogen atoms/molecule)
Number of atoms of hydrogen = 6.012 x 10^23 hydrogen atoms
Therefore, you would expect to make approximately 6.012 x 10^23 atoms of hydrogen in the compound NH3.