Kim rolls two number cubes 60 times. How many times can she expect the sum of the numbers to be greater than 10

You are looking for 6,5 or 5,6 or 6,6, which are 3/36 * 60.

To find out how many times Kim can expect the sum of the numbers to be greater than 10 when rolling two number cubes 60 times, we need to understand the probability of getting a sum greater than 10 in a single roll and then calculate the expected number of times based on this probability.

To begin, we need to determine the total number of outcomes when rolling two number cubes. Each number cube has six faces, so the total number of outcomes is 6 multiplied by 6, which equals 36.

Next, we need to count the number of outcomes where the sum of the numbers is greater than 10. Let's list them:
- The sum can be 11 with one possibility: (5, 6) or (6, 5).
- The sum can be 12 with two possibilities: (6, 6).
- The sum can be 13 with one possibility: (6, 6).
- The sum can be 14 with one possibility: (6, 6).
- The sum can be 15 with one possibility: (6, 6).
- The sum can be 16 with one possibility: (6, 6).

So, the total number of outcomes where the sum is greater than 10 is 1 + 2 + 1 + 1 + 1 + 1, which equals 7.

Now, we can calculate the probability of getting a sum greater than 10 in a single roll by dividing the number of desired outcomes by the total number of outcomes:
Probability = Number of desired outcomes / Total number of outcomes
Probability = 7 / 36

To find the expected number of times Kim can expect the sum to be greater than 10 in 60 rolls, we multiply the probability by the number of rolls:
Expected number = Probability * Number of rolls
Expected number = (7 / 36) * 60

Therefore, Kim can statistically expect the sum of the numbers to be greater than 10 approximately 11 times when rolling two number cubes 60 times.