Determine the acceleration of an electron placed in a constant downward electric field of 4.0X10^5N/C.
F = Eq = ma
Have to look up the mass of an electron. It's charge is 1.6e-19 tho.
And remember direction of an E field is determined by a POSITIVE test charge. So which way will your electron go?
I need solution for the above problem
Formula to determine acceleration of a motion of an electron placed in a constant downward electric field
To determine the acceleration of an electron placed in a constant downward electric field, we can apply Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
In this case, the net force acting on the electron is the product of its charge (e = -1.6 × 10^-19 C) and the electric field strength (E = 4.0 × 10^5 N/C). The negative sign indicates that the force is acting in the opposite direction to the electric field.
F_net = e * E
Next, we need to calculate the mass of the electron. The mass of an electron is approximately 9.11 × 10^-31 kg.
Now, we can substitute these values into Newton's second law equation:
F_net = m * a
e * E = m * a
Solving for acceleration (a), we can rearrange the equation:
a = (e * E) / m
Plugging in the values, we get:
a = (-1.6 × 10^-19 C * 4.0 × 10^5 N/C) / (9.11 × 10^-31 kg)
Now, let's calculate the acceleration:
a = -7.04 × 10^5 m/s^2
Therefore, the acceleration of the electron in the constant downward electric field is approximately -7.04 × 10^5 m/s^2. Note that the negative sign indicates the direction of acceleration, which is opposite to the electric field direction.