Some hydrogen is collected over water at 10 degrees C and 105.5 kPa pressure. The total volume of the sample was 1.93 L. Calculate the volume of the hydrogen or reacted to STP.
I don't get the "or reacted". I assume you want the volume of H2 corrected to STP.
Look up the vapor pressure of water at 10 C.
Ptotal = pH2O + pH2
105.5 = vap pressure H2O + pH2 and solve for pH2.
Then PV = nRT and solve for V.
Remember to use the same units for ptotal and vapor pressure of H2O at 10 C. Also, if you use P in kPa the R is 8.314. Also remember T must be in kelvin.
I am sorry I think autocorrect changed it to that. It is supposed to so corrected no or reacted.
Thank you so much.
Well, let me do some clown math for you! First, let's convert the pressure to the correct units for STP, which is 101.3 kPa. So, we have hydrogen at 105.5 kPa feeling a little bit of pressure to fit in. Now, let's use the combined gas law to relate the initial conditions to STP conditions.
Using the combined gas law, we have:
(P1 x V1) / (T1) = (P2 x V2) / (T2)
Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure
V2 = final volume (which we want to find)
T2 = final temperature (in this case, at STP)
Given:
P1 = 105.5 kPa
V1 = 1.93 L
T1 = 10 degrees C + 273.15 (to convert to Kelvin) = 283.15 K
P2 = 101.3 kPa
T2 = 273.15 K (STP temperature)
Now, let's plug in the values:
(105.5 kPa x 1.93 L) / (283.15 K) = (101.3 kPa x V2) / (273.15 K)
Cross-multiplying, we get:
(105.5 kPa x 1.93 L x 273.15 K) = (101.3 kPa x V2 x 283.15 K)
After doing all the math, we find that V2, the volume of hydrogen reacted to STP, is approximately 2.03 L.
So there you have it! The volume of hydrogen reacted to STP is approximately 2.03 L. But remember, this is clown math, so take it with a pinch of glitter!
To calculate the volume of the hydrogen reacted to STP (Standard Temperature and Pressure), we need to first convert the given conditions to STP.
STP is defined as a temperature of 0 degrees Celsius (273.15 K) and a pressure of 101.3 kPa.
Given:
Temperature (T) = 10 degrees Celsius = 10 + 273.15 K = 283.15 K
Pressure (P) = 105.5 kPa
Volume (V) = 1.93 L
Now, we can use the combined gas law equation to relate the initial conditions to the conditions at STP:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 = Initial pressure
V1 = Initial volume
T1 = Initial temperature
P2 = Final pressure (STP)
V2 = Final volume (STP)
T2 = Final temperature (STP)
Rearranging the equation gives:
V2 = (P1 * V1 * T2) / (P2 * T1)
Plugging in the values:
V2 = (105.5 kPa * 1.93 L * 273.15 K) / (101.3 kPa * 283.15 K)
Calculating this expression will give us the volume of the hydrogen reacted to STP.