Suppose
f(x)=3x−2.
Then
f(1) =
f(t) =
f(x2) =
f(f(x)) =
just plug and chug.
f(x^2) = 3x^2-2
f(f(x)) = 3f(x)-2 = 3(3x-2)-2 = 9x-8
the others are trivial.
The answers don't seem to be correct?
To find the values of the given expressions, we need to substitute the respective values into the function f(x) = 3x - 2.
1. f(1):
To evaluate f(1), substitute x = 1 into the function:
f(1) = 3(1) - 2 = 1.
2. f(t):
To evaluate f(t), substitute x = t into the function:
f(t) = 3(t) - 2 = 3t - 2.
3. f(x2):
To evaluate f(x^2), substitute x = x^2 into the function:
f(x2) = 3(x^2) - 2 = 3x^2 - 2.
4. f(f(x)):
To evaluate f(f(x)), substitute x = f(x) into the function:
f(f(x)) = 3(f(x)) - 2.
Since x = f(x), we replace x with f(x), giving us:
f(f(x)) = 3(f(x)) - 2 = 3(3x - 2) - 2 = 9x - 6 - 2 = 9x - 8.
Therefore,
f(1) = 1,
f(t) = 3t - 2,
f(x2) = 3x^2 - 2,
f(f(x)) = 9x - 8.