A string stretched between two supports sets up standing waves with two nodes between the ends when driven at a frequency of 230Hz.What order is such a wave?
third order. the string is 1.5 wavelengths long.
To determine the order of a standing wave, we need to consider the number of nodes present between the ends of the string. In this case, the problem states that there are two nodes between the ends when the string is driven at a frequency of 230 Hz.
The order of a standing wave refers to the number of complete waves (also known as half-wavelengths) present in the string. Each complete wave contains one node and one antinode. Since there are two nodes between the ends, we can conclude that there must be a total of four half-wavelengths.
To find the order of the wave, we count the number of half-wavelengths (or complete waves) between the two ends. Since there are four half-wavelengths, we divide this number by 2 to get the order of the wave.
Order = (Number of half-wavelengths) / 2
Order = 4 / 2 = 2
Therefore, the order of the standing wave in this scenario is 2.