What mass of AgCl(143.32g/mol) is formed from the reaction of a 0.109 M MgCl2 solution with excess AgC2H3O2?
2AgC2H3O2 + MgCl2 ==> 2AgCl + Mg(C2H3O2)2
mols MgCl2 = grams/molar mass = ?
Using the coefficients in the balanced equation convert mols MgCl2 to mols AgCl.
Then convert mols AgCl to mass. g AgCl = mols AgCl x molar mass AgCl.
To determine the mass of AgCl formed, we need to use the balanced equation for the reaction between MgCl2 and AgC2H3O2:
2AgC2H3O2 + MgCl2 -> 2AgCl + Mg(C2H3O2)2
From the equation, we can see that 2 moles of AgC2H3O2 react with 1 mole of MgCl2 to produce 2 moles of AgCl.
First, we need to determine the moles of MgCl2 in the solution.
Given:
Molarity of MgCl2 solution (M) = 0.109 M
Volume of MgCl2 solution (L) = let's assume it to be 1 liter
Moles of MgCl2 = Molarity x Volume
= 0.109 mol/L x 1 L
= 0.109 mol
Since the reaction uses a 1:1 ratio between MgCl2 and AgCl, the moles of AgCl formed will also be 0.109 mol.
Next, we can calculate the mass of AgCl formed using its molar mass:
Molar mass of AgCl = 143.32 g/mol
Mass of AgCl = Moles of AgCl x Molar mass of AgCl
= 0.109 mol x 143.32 g/mol
≈ 15.61 g
Therefore, approximately 15.61 grams of AgCl will be formed in the reaction.
To find the mass of AgCl formed, we need to use the stoichiometry of the reaction and the concentration of MgCl2.
The balanced chemical equation for the reaction is:
MgCl2 + 2AgC2H3O2 -> 2AgCl + Mg(C2H3O2)2
From the balanced equation, we can see that 1 mole of MgCl2 reacts with 2 moles of AgC2H3O2 to produce 2 moles of AgCl. Therefore, the mole ratio of MgCl2 to AgCl is 1:2.
First, let's find the number of moles of MgCl2:
Given the concentration of MgCl2 solution is 0.109 M, which means there are 0.109 moles of MgCl2 in 1 liter of solution (according to the definition of molarity, M).
Let's assume the volume of the solution used in the reaction is V liters.
Therefore, the number of moles of MgCl2 used in the reaction is equal to (0.109 mol/L) multiplied by V.
Now, using the mole ratio, we can determine the number of moles of AgCl formed in the reaction:
For every 1 mole of MgCl2, 2 moles of AgCl are produced. So, the number of moles of AgCl is 2 times the number of moles of MgCl2 used in the reaction.
Finally, to find the mass of AgCl formed, we use the molar mass of AgCl (143.32 g/mol) and the number of moles of AgCl.
Mass of AgCl = number of moles of AgCl * molar mass of AgCl
By plugging in the values, we can calculate the mass of AgCl formed.