a box is 11 inches tall, 2 inches deep, and 8 inches wide. What is the surface area of the box that is needed for the cereal
{2(11*2)} + {2(11*8)} + {2(8*2)} = ______ square inches
Determine the SURFACE AREA of the current cereal box, with dimensions
12 inches high
8 inches long
2 inches deep
To find the surface area of the box, we need to calculate the area of each side and then sum them up.
The box has six sides - a top, a bottom, a front, a back, a left side, and a right side.
1. Top and bottom: The top and bottom sides have the same dimensions, so we'll calculate their area together. The formula for the area of a rectangle is length × width. In this case, the length is 8 inches (width of the box) and the width is 2 inches (depth of the box), so the area of the top and bottom sides is 8 inches × 2 inches = 16 square inches.
2. Front and back: The front and back sides also have the same dimensions. The length is 8 inches (width of the box) and the height is 11 inches, so the area of the front and back sides is 8 inches × 11 inches = 88 square inches.
3. Left and right sides: The left and right sides have the same dimensions. The length is 2 inches (depth of the box) and the height is 11 inches, so the area of the left and right sides is 2 inches × 11 inches = 22 square inches.
To find the total surface area, add up the areas of all six sides: 16 square inches (top and bottom) + 88 square inches (front and back) + 22 square inches (left and right) = 126 square inches.
Therefore, the surface area of the box needed for the cereal is 126 square inches.
@ Ms.Sue,
44+168+32=(168+32)+44=200+44=244