Each course at college X is worth either 3 or 4 credits. The members of the men's swim team are taking a total of 52 courses that are worth a total of 169 credits. How many 3-credit courses and how many 4-credit courses are being taken?
Let's assume the number of 3-credit courses taken is represented by 'x'.
So, the number of 4-credit courses taken can be represented by '52 - x'.
Given that each 3-credit course is worth 3 credits and each 4-credit course is worth 4 credits, the total credits of the 3-credit courses would be 3x and the total credits of the 4-credit courses would be 4(52 - x).
According to the problem, the total credits are 169. So, we can write the equation as:
3x + 4(52 - x) = 169
Solving this equation will give us the values of 'x' and (52 - x), which represent the number of 3-credit courses and 4-credit courses respectively.
Let's solve the equation:
3x + 208 - 4x = 169
-x = 169 - 208
-x = -39
x = 39
Therefore, the number of 3-credit courses being taken is 39, and the number of 4-credit courses being taken is (52 - 39) = 13.
To determine the number of 3-credit and 4-credit courses being taken by the members of the men's swim team, we can set up a system of equations.
Let's assume that the number of 3-credit courses is x, and the number of 4-credit courses is y.
According to the problem statement, the total number of courses taken is 52, so we have the equation:
x + y = 52
Additionally, the total number of credits for these courses is 169, so we have another equation:
3x + 4y = 169
Now we can solve this system of equations to determine the values of x and y.
One method to solve this system is by substitution:
From the first equation, we can rewrite it as x = 52 - y.
Substituting this into the second equation, we get:
3(52 - y) + 4y = 169
Simplifying, we have:
156 - 3y + 4y = 169
Combining like terms, we get:
y = 169 - 156
y = 13
Now, substituting this value back into the first equation, we can solve for x:
x + 13 = 52
x = 52 - 13
x = 39
Therefore, the members of the men's swim team are taking 39 courses worth 3 credits each and 13 courses worth 4 credits each.
Look at the response to this question last night by both Steve and I.
All you have to do is change the original second equation, and solve.
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