An electric lamp rated at 48w,12-v supply. Calculate the current flowing in the lamp and the resistance
Since P=48w
And V=12v
And I=?
So therefore
N/B P=IV
48=I*12
Divide both side by 12
48/12 = I 12/12
I = 4ampere
power=current*voltage
current=power/volts=4amps
Resistance=voltage/current
To calculate the current flowing in the lamp, we can use Ohm's Law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R), expressed as I = V / R.
In this case, the voltage (V) is 12 volts and the power (P) of the lamp is 48 watts. Power is calculated as the product of voltage and current, so P = V * I.
We can rearrange this equation to solve for current (I):
I = P / V
Substituting the given values:
I = 48 watts / 12 volts = 4 amps
Therefore, the current flowing in the lamp is 4 amps.
To calculate the resistance (R), we can use Ohm's Law again:
R = V / I
Substituting the given values:
R = 12 volts / 4 amps = 3 ohms
Therefore, the resistance of the lamp is 3 ohms.
To calculate the current flowing through the lamp, we can use Ohm's Law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R).
First, let's calculate the current:
Given:
Power (P) = 48W
Voltage (V) = 12V
Power is given by the equation:
P = V * I
Rearranging the equation, we get:
I = P / V
Substituting the given values, we have:
I = 48W / 12V
I = 4 Amperes (A)
So, the current flowing through the lamp is 4 Amperes.
Now, to calculate the resistance, we can use Ohm's Law:
R = V / I
Substituting the values:
R = 12V / 4A
R = 3 ohms (Ω)
Therefore, the resistance of the electric lamp is 3 ohms.