Question

Find an expression for dy/dx

y^3+(1/y)=x^2-7y

Answer 1

3 y^2 dy/dx - dy/dx / y^2 = 2 x -7 dy/dx

dy/dx (3 y^2 -1/y^2 + 7) = 2 x

dy/dx = 2 x /[ 3 y^2 -y^-2 + 7 ]