The sum of two numbers is 120. If four times four times the smaller number is subtracted from the larger number, the result is 15. Find the two numbers.
N+M=120
M-4N=15
solve for n, m.
Your school subject is not ps 27. That's where you go to school. Your subject seems to be math.
To solve this problem, let's assign variables to the unknown numbers. Let's call the smaller number "x" and the larger number "y".
We know that the sum of the two numbers is 120, so we can write the equation:
x + y = 120 -- (Equation 1)
We also know that when four times the smaller number is subtracted from the larger number, the result is 15. Mathematically, we can express this as:
y - 4x = 15 -- (Equation 2)
Now, we have two equations with two variables. We can use any method like substitution or elimination to solve for x and y.
Let's use the substitution method:
1. Solve Equation 1 for y:
y = 120 - x
2. Substitute this value of y into Equation 2:
120 - x - 4x = 15
3. Simplify the equation by combining like terms:
120 - 5x = 15
4. Move the constant term to the other side:
-5x = 15 - 120
5. Simplify further:
-5x = -105
6. Divide both sides of the equation by -5 to solve for x:
x = -105 / -5
x = 21
Now that we have found the value of x, we can substitute it back into Equation 1 to find y:
y = 120 - x
y = 120 - 21
y = 99
Therefore, the two numbers are 21 and 99.