Compare the graphs of the inverse variations. Please provide at least 3 comparisons? y= (-0.2/x) and y= (-0.3/x)
is this correct as an answer?
1, -0.2, -0.3
2, -0.1, -0.15
3, -0.0667, -0.1
No, the comparisons you provided are not correct. To compare the graphs of inverse variations, we need to understand the general form of an inverse variation equation, which is y = k/x, where k is a constant. In this case, we have two inverse variation equations:
1. y = (-0.2/x)
2. y = (-0.3/x)
To compare these graphs, we can look at the values of y for different values of x. Let's find the value of y for x = 1, x = 2, and x = 3 for both equations:
For y = (-0.2/x):
- When x = 1, y = -0.2/1 = -0.2
- When x = 2, y = -0.2/2 = -0.1
- When x = 3, y = -0.2/3 ≈ -0.0667
For y = (-0.3/x):
- When x = 1, y = -0.3/1 = -0.3
- When x = 2, y = -0.3/2 = -0.15
- When x = 3, y = -0.3/3 = -0.1
Now we can compare the results:
1. The first comparison is correct. For both equations, when x = 1, y = -0.2 and y = -0.3, respectively.
2. The second comparison is incorrect. For y = (-0.2/x), when x = 2, y = -0.1, but for y = (-0.3/x), when x = 2, y = -0.15.
3. The third comparison is incorrect as well. For y = (-0.2/x), when x = 3, y ≈ -0.0667, but for y = (-0.3/x), when x = 3, y = -0.1.
Hence, the correct comparisons are:
1. When x = 1, y = -0.2 and y = -0.3 for the two equations.
2. When x = 2, y = -0.1 for y = (-0.2/x) and y = -0.15 for y = (-0.3/x).
3. When x = 3, y ≈ -0.0667 for y = (-0.2/x) and y = -0.1 for y = (-0.3/x).