A truck leaves an intersection going 42 miles per hour. Half an hour later, a car going 62 miles per

hour follows the truck. If x is the time, in hours, required for the car to catch the truck, then which of
the following equations can be used to solve for x?

Since x is the amount of time it takes for both vehicles to travel a distance specified. you set those 2 rates equal to each other. In the Problem, it specifies that the starting points for both vehicles are not the same. The Truck has a half an hour head start on the car, and since we know the rate at which the car is traveling. We can find the difference in starting points.

The truck travels 42m/h * .5h = 21m.
42x + 21 = 62x

I FIND IT DIFFICULT

Well, this sounds like a classic case of "catch me if you can" on the highway! To solve for x, we need an equation that considers the speeds and times of both the truck and the car.

Since the truck leaves half an hour earlier, we can express the truck's time in terms of x. The car's time will simply be x, as it starts half an hour later.

Let's assume the truck's time is (x + 0.5) hours, as it started half an hour earlier. The distance covered by the truck in this time will be 42 * (x + 0.5) miles.

The car's distance covered will be 62 * x miles, as it starts half an hour later.

Now, for the equations:

A. 42x = 62(x + 0.5)
B. 42(x + 0.5) = 62x
C. 42(x + 0.5) = 62(x - 0.5)
D. 42(x - 0.5) = 62(x + 0.5)

Let's find the humor in this situation:

Hmm, it seems like the truck and the car are engaged in a little game of "catch me if you can". The truck starts early, thinking it has an advantage, but the car is determined to catch up!

To find the equation that solves for x, we need to make sure the distances covered by the truck and the car are equal. That's when the car finally catches up to the truck.

After some pondering, the equation that captures this moment of catch-up is Option B. So, B - is the answer!

Keep driving safely, and remember, it's not always about who gets there first, but about enjoying the ride!

To solve this problem, we need to set up an equation using the information given.

Let's denote the time it takes for the car to catch the truck as x hours.

Since the truck left half an hour earlier, it has been traveling for half an hour plus x hours.

Using the formula distance = speed * time, we can determine the distances covered by the truck and the car.

The distance covered by the truck can be calculated as 42 * (x + 0.5) (since it left half an hour earlier).

The distance covered by the car can be calculated as 62 * x.

Since they meet at the same point, the distances covered by both the truck and the car should be equal. Therefore, we can set up an equation:

42 * (x + 0.5) = 62 * x

Now, let's simplify the equation:

42x + 21 = 62x

Rearranging the terms:

62x - 42x = 21

20x = 21

Dividing both sides by 20:

x = 21/20

So, the equation that can be used to solve for x is:

42(x + 0.5) = 62x

Not sure about your invisible equations, but mine would be

42x = 62(x - 1/2)