for the sequence 1,4,7,11,13 find the 11th term of the sequence solution;
Tn=a+(n-1)d
T11=1+(11-1)3
1+(10)3
30
should this be
1,4,7,10,13,...
To find the 11th term of the sequence 1, 4, 7, 11, 13, you can use the formula for the nth term of an arithmetic sequence. The formula is:
Tn = a + (n - 1)d
Where:
Tn = the nth term of the sequence
a = the first term of the sequence
n = the position of the term you want to find
d = the common difference between consecutive terms
In this case, the first term (a) is 1 and the common difference (d) is 3.
To find the 11th term (T11), you substitute these values into the formula:
T11 = 1 + (11 - 1) * 3
T11 = 1 + 10 * 3
T11 = 1 + 30
T11 = 31
Therefore, the 11th term of the sequence is 31.