in a rational number... nemerator is 3 less than the denominator. if 3 is added to the numerator.. fraction becomes 1. find the fraction??
3/6
Yourself
To solve this problem, let's represent the numerator as "n" and the denominator as "d."
According to the given information, the numerator (n) is 3 less than the denominator (d). So we can write the equation: n = d - 3
We are also told that if 3 is added to the numerator, the fraction becomes 1. Therefore, we can write another equation: (n + 3) / d = 1
Now we have a system of two equations:
Equation 1: n = d - 3
Equation 2: (n + 3) / d = 1
To find the fraction, we need to solve this system of equations.
Let's substitute the value of n from Equation 1 into Equation 2:
((d - 3) + 3) / d = 1
(d - 3 + 3) / d = 1
d/d = 1
By canceling out the d's on the left side, we get:
1 = 1
This equation is always true, which means that the value of d can be any number. Since d is the denominator, we can choose any positive integer value for d.
Let's assume d = 4.
Then, we can substitute this value of d into Equation 1 to find the numerator:
n = d - 3
n = 4 - 3
n = 1
So, when the numerator (n) is 1 and the denominator (d) is 4, the fraction is 1/4.
Therefore, the fraction is 1/4.