There is a jar with 16 marbles. 4 are red, 7 are blue, and 5 are green. You select two marble at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability of selecting a red marble and then another red marble?
a. 3/64
b. 1/4
c. 1/20
d. 1/30
I think it’s c, correct me if I’m wrong.
since the marble is not replaced,
P(red,red) = 4/16 * 3/15 = 1/20
you are correct
Awesome, thanks Steve!
Green marble=40,blue marble=202,red marble=26.what is the red marble (%)?
To find the probability of selecting a red marble and then another red marble, we need to break down the problem into two steps.
Step 1: Selecting the first red marble
Out of the 16 marbles, there are 4 red marbles. So the probability of selecting a red marble is 4/16.
Step 2: Selecting the second red marble
After the first marble is drawn and not replaced, there are now 15 marbles left in the jar. Since one red marble was already selected, there are only 3 red marbles remaining. So the probability of selecting a second red marble is 3/15.
To get the probability of both events happening together (selecting a red marble and then another red marble), we multiply the probabilities from each step:
(4/16) * (3/15) = 12/240 = 1/20
So the correct answer is c. 1/20.