A tank is one-third full of oil.after taking out 7 litres from it,it is now only one-fourth full. How much oil does the tank hold?
Please provide how you solved the problem
thanks
If the full tank holds x liters, they have told you that
x/3 - 7 = x/4
Now just solve for x.
x/3-7=x/4
Get the lcd which is 12.
12*x/3-12*7=12*x/4
4x-84=3x
you take 3x to the other side of the opposite side and the sign changes to -3x
4x-3x=x
x=84
x/3-7=x/4
Get the lcd which is 12.
12*x/3-12*7=12*x/4
4x-84=3x
you take 3x to the other side of the opposite side and the sign changes to -3x
4x/12-3x12=x/12=84
x/12=84
12=84x12=1008 litres
To solve this problem, we can set up an equation using the given information.
Let's assume the tank can hold "x" liters of oil.
According to the problem, initially, the tank is one-third full. So, the amount of oil in the tank is (1/3) * x liters.
After taking out 7 liters, the tank is now one-fourth full. So, the amount of oil in the tank is (1/4) * x liters.
We can now set up the equation:
(1/3) * x - 7 = (1/4) * x
To eliminate the fractions, we can multiply both sides of the equation by 12 (which is the least common multiple of 3 and 4):
12 * ((1/3) * x - 7) = 12 * ((1/4) * x)
4x - 84 = 3x
Subtract 3x from both sides:
4x - 3x - 84 = 0
x - 84 = 0
Add 84 to both sides:
x = 84
Therefore, the tank can hold 84 liters of oil.