Your search for statistics test questions a professor is trying to convince her colleagues that peer tutoring works. she compares the results of students in two classes one with and one without the peer tutoring. for the non-tutored group the mean score fore for 35'studentsnis 81 with a sigmaofm7. for the tutored group the mean for 40 students was 85 with a sigms of 4. do theses results suggest that the tutoring works? ( sigma=.05) did not match with any Answers results. Can u workout thank u

Question

Your search for statistics test questions a professor is trying to convince her colleagues that peer tutoring works. she compares the results of students in two classes one with and one without the peer tutoring. for the non-tutored group the mean score fore for 35'studentsnis 81 with a sigmaofm7. for the tutored group the mean for 40 students was 85 with a sigms of 4. do theses results suggest that the tutoring works? ( sigma=.05) did not match with any Answers results. Can u workout thank u

Answer 1

Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√n

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.