Warren walked 4 kilometers down east and then 5 kilometers down south. Next, he walked another 4 kilometers down east. Then he turned again, and walked 5 kilometers down south. He stopped there. To the nearest kilometer, how far is he from the starting point?

East: 4 + 4 = 8

South: 5 + 5 = 10

Those are two legs of a right triangle.

Use the Pythagorean Theorem to find the hypotenuse of this triangle.

Is it 12 Kilometers

correct or no?

To find the distance between Warren's final position and the starting point, we can use the concept of coordinates.

Let's assume Warren's starting point is the origin, (0,0), on a two-dimensional coordinate plane, with the x-axis representing east-west direction and the y-axis representing north-south direction.

First, Warren walks 4 kilometers down east, which means he moves 4 units in the positive x-direction. His new position would be (4,0).

Next, he walks 5 kilometers down south, meaning he moves 5 units in the negative y-direction. This changes his position to (4,-5).

Then, Warren walks another 4 kilometers down east, taking him to coordinates (8,-5).

Finally, he turns and walks 5 kilometers down south. This means he moves another 5 units in the negative y-direction, changing his position to (8,-10).

To find the distance between Warren's final position and the starting point, we can use the Pythagorean theorem. The distance, d, is given by:
d = √((x₂ - x₁)² + (y₂ - y₁)²)

Using the coordinates, the distance is:
d = √((8 - 0)² + (-10 - 0)²)
d = √(64 + 100)
d = √164
d ≈ 12.81

Therefore, Warren is approximately 13 kilometers away from the starting point.