A(n) 0.251 kg soccer ball approaches a player
horizontally with a speed of 15.8 m/s. The
player illegally strikes the ball with her hand
and causes it to move in the opposite direction
with a speed of 27.3 m/s.
What is the magnitude of the impulse delivered
to the ball by the player?
Answer in units of kg m/s.
Ft = change in mv, that is mvf-mvi. Be careful on this one. If you choose to make the initial positive you must make the final negative because it's going in the opposite direction. And note you don't need to find F or t, the impulse IS Ft.
To find the magnitude of the impulse delivered to the ball by the player, we can use the formula for impulse:
Impulse = Change in momentum
We can calculate the change in momentum by subtracting the initial momentum of the ball from its final momentum.
To find the initial momentum, we multiply the mass of the soccer ball by its initial velocity:
Initial momentum = mass * initial velocity
Initial momentum = 0.251 kg * 15.8 m/s
To find the final momentum, we multiply the mass of the soccer ball by its final velocity:
Final momentum = mass * final velocity
Final momentum = 0.251 kg * -27.3 m/s (since the ball moves in the opposite direction)
Now, we can calculate the change in momentum:
Change in momentum = Final momentum - Initial momentum
Change in momentum = (0.251 kg * -27.3 m/s) - (0.251 kg * 15.8 m/s)
Finally, we can calculate the magnitude of the impulse, which is the absolute value of the change in momentum:
Magnitude of the impulse = |Change in momentum|
Therefore, to find the magnitude of the impulse delivered to the ball by the player, we need to calculate the change in momentum and then take its absolute value.