Determine the vapor pressure (in atm) of water in an aqueous solution of 12% by mass ethylene group (antifreeze) if the vapor pressure of pure water at that temperature is 0.095 atmospheres.
Calculate mole fraction ethylene glycol. Then
Psolution = Xsolution *Po H2O
You would do well to use the same screen names for your posts.
To determine the vapor pressure of water in an aqueous solution of ethylene glycol (antifreeze), you can use Raoult's Law. According to Raoult's Law, the vapor pressure of a component in a solution is equal to the product of its mole fraction in the solution and its vapor pressure in the pure state.
First, you need to calculate the mole fraction of water in the solution. Since the solution is 12% by mass ethylene glycol, the remaining 88% must be water.
Mole fraction of water = mass fraction of water / molar mass of water
Mass fraction of water = 88% = 0.88
Molar mass of water = 18.02 g/mol
Mole fraction of water = 0.88 / 18.02 = 0.0488
Now, you can use Raoult's Law to calculate the vapor pressure of water in the solution.
Vapor pressure of water in solution = mole fraction of water * vapor pressure of water in pure state
Vapor pressure of water in solution = 0.0488 * 0.095 atm
Therefore, the vapor pressure of water in the aqueous solution of 12% by mass ethylene glycol is approximately 0.0046 atm.