Eric is twice as old as Jared. the sum of their ages 10 years ago was 19years what is Jared age now.Give me the answer
Now:
Jared --- x
Eric ---- 2x
10 years ago:
Jared --- x - 10
Eric -----2x-10
x-10 + 2x-10 = 19
solve for x
13
To find Jared's current age, we can follow these steps:
1. Let's assign variables to represent their ages. Let's say Eric's current age is E and Jared's current age is J.
2. The problem states that Eric is twice as old as Jared, so we have the equation: E = 2J.
3. It is also given that the sum of their ages 10 years ago was 19. So, we can create the equation: (E - 10) + (J - 10) = 19.
4. Now, substitute E in the second equation with 2J from the first equation: (2J - 10) + (J - 10) = 19.
5. Simplify the equation: 3J - 20 = 19.
6. Add 20 to both sides to isolate 3J: 3J = 39.
7. Divide both sides by 3 to solve for J: J = 13.
Therefore, Jared's current age is 13.