Locate the centre of mass of a system of two spherical masses of 5kg and 10kg kept with their centres 1m apart

The work done by boy pulling a snow sled up a hill is 425 j.what is the power expended by the boy if he pulls on the sled for 10.5s?

The work done by boy pulling a snow sled up a hill is 425 j.what is the power expended by the boy if he pulls on the sled for 10.5s?please

To locate the center of mass of a system of two spherical masses, you need to consider the masses and their distances from a reference point.

In this case, we have two spherical masses of 5 kg and 10 kg with their centers kept 1 m apart. Let's assume one mass is mass A and the other is mass B.

Step-by-step procedure:

1. Assign a coordinate system: Choose a reference point as the origin (0,0) of your coordinate system. The position of mass A will be (-1,0) and the position of mass B will be (1,0) due to the 1 m distance between their centers.

2. Calculate the center of mass along the x-axis:
- Mass A contributes to the center of mass at (-1, 0) with a weightage of 5 kg.
- Mass B contributes to the center of mass at (1, 0) with a weightage of 10 kg.
- To find the x-coordinate of the center of mass (x_cm), use the formula:
x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Substitute the values:
x_cm = (5 kg * -1 m + 10 kg * 1 m) / (5 kg + 10 kg)
= (-5 kg m + 10 kg m) / (15 kg)
= 5 kg m / 15 kg
= 1/3 m

Therefore, the x-coordinate of the center of mass is 1/3 m.

3. Calculate the y-coordinate of the center of mass:
- Since both masses are located on the x-axis, there is no contribution to the center of mass along the y-axis.
- Therefore, the y-coordinate of the center of mass (y_cm) is 0.

4. Result:
The center of mass of the system is located at (1/3, 0) m (x_cm, y_cm).

2/3 of the from the 5kg mass, since

2*5 = 1*10