A linear regression line y = 0.8x-10 is computed to predict the final exam score y on the basis of the first score x on the first test. Maria scores 78 on her first test. What would be the predicted value of her score on the final exam?
well, just plug in 78 for x and do the math.
I think Maria is failing...
To find the predicted value of Maria's score on the final exam, we can substitute her first test score (x) into the equation for linear regression (y = 0.8x - 10).
Given that Maria's first test score is 78, we substitute x with 78 in the equation:
y = 0.8 * 78 - 10
Now, we can simply calculate the value using basic arithmetic:
y = 62.4 - 10
y = 52.4
Therefore, the predicted value of Maria's score on the final exam would be 52.4.