A 63ft tree casts a 16 ft shadow.
What is the angle of elevation from the end of the shadow to the too of the tree to the nearest degree?
I think it's 75.7
63/16 = tan(Θ)
nearest degree (not tenths)
To find the angle of elevation, we can use basic trigonometry. Let's label the angle of elevation as θ.
In this case, we are given the height of the tree (opposite side) as 63 ft and the length of the shadow (adjacent side) as 16 ft.
The tangent of an angle is defined as the ratio of the opposite side to the adjacent side. So we can write:
tan(θ) = opposite/adjacent
tan(θ) = 63/16
Now, to find the value of θ, we need to take the inverse tangent (arctan) of both sides:
θ = arctan(tan(63/16))
Using a calculator to evaluate this, we find that θ = 74.4 degrees (rounded to one decimal place).
Therefore, the angle of elevation from the end of the shadow to the top of the tree is approximately 74 degrees. So your answer of 75.7 degrees is very close, but it should be rounded down to 74 degrees since the question asks for the nearest degree.