Draw the structures of the three primary (1°) amines with molecular formula C5H13N that contain five carbon atoms in a continuous chain.
To draw the structures of the three primary (1°) amines with the molecular formula C5H13N that contain five carbon atoms in a continuous chain, we need to consider the various ways in which the carbon and nitrogen atoms can be arranged. Here's how to do it:
1. Start with the molecular formula C5H13N, which tells us that the molecule contains 5 carbon atoms (C5) and 1 nitrogen atom (N), with a total of 13 hydrogen atoms (H13).
2. Since we want a continuous chain of five carbon atoms, we can arrange them in different ways: in a straight line, with branching, or in a ring.
3. Let's begin with the straight chain. To have a primary amine, the nitrogen atom must be at one of the terminal positions of the chain. So, we can draw the following structure:
H
|
H - C - C - C - C - N - H
|
H
In this structure, we have a continuous chain of five carbon atoms (C-C-C-C-C) with one terminal nitrogen (N) atom bonded to a hydrogen (H) atom.
4. Now, let's consider the possibilities with branching. The nitrogen atom can be bonded to one of the internal carbon atoms, resulting in a branched structure. There are two possible positions for the nitrogen atom:
a) Nitrogen bonded to the second carbon atom in the chain:
H
|
H - C - N - C - C - C - H
|
H
b) Nitrogen bonded to the third carbon atom in the chain:
H
|
H - C - C - N - C - C - H
|
H
In both structures, we have a continuous chain of five carbon atoms (C-C-C-C-C) with one interior nitrogen (N) atom bonded to a hydrogen (H) atom.
Therefore, we have three primary amines with the molecular formula C5H13N that contain five carbon atoms in a continuous chain. These are:
1. Pentylamine (straight chain with the nitrogen at the terminal position)
2. 2-Aminopentane (branched chain with the nitrogen bonded to the second carbon atom)
3. 3-Aminopentane (branched chain with the nitrogen bonded to the third carbon atom)
Hope this helps!