Math  Could Someone Check My Work?
posted by Sami
Could someone check my work please? Thank you!
(14a^2b)(2ab^2c) = 28a^3b^3c
(a^25)^7 = a^125
6x^6 ∙ 6x^6 = 36^12
(2x^2)^3 = 8x^6
(2)0 = 1
30x^20/(6x^9 = 5x^11
4x^5 ∙ 6x^6 = 24x^11
(2x^4)^3 = 8x^12
4^2 = 16
(193)^0 = 1
(193)0 = 1
(5)2 = 25
((6x^7)/(2x^2 ))^2 = 9x^45???????
(6x&6)(6x^2x^6)  I have no idea how to solve this one. HELP PLEASE!

Reiny
(14a^2b)(2ab^2c) = 28a^3b^3c ✔
(a^25)^7 = a^125 ✔
6x^6 ∙ 6x^6 = 36^12 no,
keep the base and add the exponents = 6^12
or multiply the bases and keep the same exponent = 36^6
(2x^2)^3 = 8x^6 ✔
(2)^0 = 1 ✔
30x^20/(6x^9 = 5x^11 ✔
4x^5 ∙ 6x^6 = 24x^11 ✔
(2x^4)^3 = 8x^12 ✔
4^2 = 16 ✔
(193)^0 = 1 ✔
(193)^0 = 1 ✔
(5)2 = 25 ✔
((6x^7)/(2x^2 ))^2 = 9x^45??????? NO
= (3x^5)^2
= 9x^10
(6x&6)(6x^2x^6) , you meant (6x^6)(6x^2x^6)
= 36x^14
= 
Sami
6x^6 ∙ 6x^6 = 36^12 no,
keep the base and add the exponents = 6^12
or multiply the bases and keep the same exponent = 36^6
Why would this be? I thought I had to multiply the 6 in each and then add the exponents in each?
((6x^7)/(2x^2 ))^2 = 9x^45??????? NO
= (3x^5)^2
= 9x^10
I redid this one before you responded and got this answer also.
(6x&6)(6x^2x^6) , you meant (6x^6)(6x^2x^6)
= 36x^14
=
I also redid this one and got this but with the extra = sign are you saying there is more to simplify because I thought this would be the final answer.
Thanks so much  I'm just trying to make certain I understand this. 
Reiny
6x^6 ∙ 6x^6 = 36^12
Your answer is wrong, should be
36x^12
looks like you missed the x
and for some reason I thought you multiplied the bases of 6 and added the exponents.
In the last question, the last = sign
is just a stray one hanging around, ignore it. 
Sami
Reiny, thanks but the original problem isn't (6x^6)(6x^6)
The original problem is (6x^6)(6x^2x^6)
So I thought I would have to simplify inside the second parentheses first to make that (6x^8) by adding the exponents (2 + 6)
Then I have (6x^6)(6x^8)
I then multiply 6 x 6 = 36
and then add the exponents to get 36x^14
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