1. A baker had 10 sacks containing the following amounts of flour:
4 ½ kg, 3 ¼ kg, 2 ½ kg, 2 ½ kg, 4kg,
3 ¼ kg, 4 ¼ kg, 5kg, 2 ½ kg, 3 ¼ kg
2. If the baker redistributed the flour equally among the ten bags, how much flour would be in each bag?
Just add them up, then divide by 10.
That would be just like finding the average.
Hint: change them to decimals, they all come out nice that way, simpler to add them that way
e.g. 4 ¼ kg = 4.25 kg
My dog is quite hip.
Except when he takes a dip.
He looks like a fool,
when he jumps in the pool,
and reminds me of a sinking ship.
To find out how much flour would be in each bag if it were redistributed equally among the ten bags, you need to calculate the total amount of flour and divide it by 10.
Here's how you can do it step by step:
1. Add up the amounts of flour in each bag:
4 ½ kg + 3 ¼ kg + 2 ½ kg + 2 ½ kg + 4kg + 3 ¼ kg + 4 ¼ kg + 5kg + 2 ½ kg + 3 ¼ kg
2. Convert all the mixed fractions into improper fractions:
4 ½ kg = 9/2 kg
3 ¼ kg = 13/4 kg
2 ½ kg = 5/2 kg
4 ¼ kg = 17/4 kg
2 ½ kg = 5/2 kg
3 ¼ kg = 13/4 kg
3. Add up the fractions:
9/2 kg + 13/4 kg + 5/2 kg + 5/2 kg + 4 kg + 13/4 kg + 17/4 kg + 5 kg
4. Convert the mixed numbers into fractions:
4 = 16/4
5 = 20/4
Now the equation becomes:
9/2 kg + 13/4 kg + 5/2 kg + 5/2 kg + 16/4 kg + 13/4 kg + 17/4 kg + 20/4 kg + 5 kg
5. Find a common denominator for all the fractions:
In this case, the common denominator is 4.
6. Add up the fractions:
(9 + 26 + 10 + 10 + 16 + 13 + 17 + 20) / 4 kg
(111) / 4 kg
7. Simplify the fraction if possible:
111 / 4 kg is an improper fraction with no common factors, so it is already in its simplest form.
8. Divide the total amount of flour by 10 to distribute it equally among the ten bags:
(111 / 4 kg) / 10 = 111 / (4 * 10) kg
(111 / 4) / 10 kg
111 / 40 kg
Therefore, each bag would have (111 / 40) kg of flour after redistributing it equally among the ten bags.