The small piston of a hydraulic lift, has an area of 0.01 m2. If a force of 250 N is applied to the small piston, find the force on the large piston if it has an area of0.05 m2.
0.007N
Plz
To find the force on the large piston, we can use Pascal's law, which states that in a hydraulic system, the pressure is transmitted equally in all directions.
First, let's calculate the pressure exerted on the small piston. We can use the formula:
Pressure = Force / Area
Substituting the given values:
Pressure on small piston = 250 N / 0.01 m^2 = 25000 Pa (Pascals)
Since pressure is transmitted equally, the pressure on the small piston would be the same as the pressure on the large piston.
Now, we can calculate the force on the large piston using the formula:
Force on large piston = Pressure x Area of large piston
Substituting the values:
Force on large piston = 25000 Pa x 0.05 m^2 = 1250 N
Therefore, the force on the large piston is 1250 N.