Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 2 L, the pressure is 1065 kPa (kilopascals). What is the pressure when the volume is
15 L?
V = k/P
That is, VP = k is constant
so, you want P such that
15P = (2)(1065)
To solve this problem using Boyle's Law, we can set up the following equation:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure (1065 kPa)
V1 = initial volume (2 L)
P2 = final pressure (unknown)
V2 = final volume (15 L)
Now, we can substitute the known values into the equation and solve for P2:
P1 * V1 = P2 * V2
1065 kPa * 2 L = P2 * 15 L
To isolate P2, divide both sides of the equation by 15 L:
(1065 kPa * 2 L) / 15 L = P2
(2130 kPa * L) / (15 L) = P2
Simplifying further:
P2 = 142 kPa
Therefore, when the volume is 15 L, the pressure is 142 kPa.