In the 2001-2002 regular season NBA team Sacramento won two games less than three times that perdio.este team played a total of 82
games in the regular season . how many games won and lost equipment sacrament during the season 2001-2002
To solve this problem, we need to translate the given information into mathematical equations and then solve them.
Let's say the number of games Sacramento won in the regular season is represented by "W" and the number of games they lost is represented by "L".
According to the given information:
- "In the 2001-2002 regular season, the team Sacramento won two games less than three times that perdio" means that the number of wins is two less than three times the number of losses. So, we can write the equation:
W = 3L - 2
- It's also given that "this team played a total of 82 games in the regular season". Since the total number of games played is the sum of wins and losses, we can write the equation:
W + L = 82
Now, we have a system of two equations with two unknowns (W and L). We can solve these equations simultaneously to find the values of W and L.
One way to solve this is by substitution. We can rearrange the first equation W = 3L - 2 as W - 3L = -2, and then substitute this value of W in the second equation:
(3L - 2) + L = 82
4L - 2 = 82
4L = 84
L = 84 / 4
L = 21
Substituting this value of L back into the first equation, we can find W:
W = 3(21) - 2
W = 63 - 2
W = 61
Therefore, the equipment Sacramento won 61 games and lost 21 games during the 2001-2002 regular season.