I am 6 feet tall,weigh 69kg slipped and fell flat in 2 seconds,hitting iron bar on side of stairs.What is the force of impact on the soles at the time of impact at the end of 2 seconds? PS:this really happened that has destroyed my soles from the force of impact injury.

That is really impossible to calculate. There is a change of momentum during the collision and force = change of momentum / duration of actual collision. That would be a fraction of a second but how long depends on the crushing characteristics of the body.

To calculate the force of impact on the soles of your feet, we need to make a few assumptions and use formulas related to physics.

Assumptions:
1. Assuming you were at rest before slipping: Initial velocity (u) = 0 m/s
2. Time (t) = 2 seconds
3. Acceleration due to gravity (g) = 9.8 m/s² (approximate value near the Earth's surface, assuming no air resistance)

To find the final velocity, we can use the formula:
v = u + gt

In this case, since your initial velocity was 0 m/s, the formula simplifies to:
v = gt

Substituting the given values:
v = 9.8 * 2
v = 19.6 m/s

Next, let's calculate the distance fallen using another formula:
s = ut + (1/2)gt²

Since the initial velocity is 0, the formula becomes:
s = (1/2)gt²

Substituting the given values:
s = (1/2) * 9.8 * (2)²
s = (1/2) * 9.8 * 4
s = 19.6 m

Now we can calculate the force of impact using another formula:
Force = mass * acceleration

Given that your weight is 69 kg, we need to find your mass first. The weight of an object on Earth can be calculated using:
weight = mass * gravitational acceleration

Rearranging the formula, we get:
mass = weight / gravitational acceleration

mass = 69 kg / 9.8 m/s²
mass ≈ 7.04 kg

Now we can calculate the force of impact:
Force = mass * acceleration

Force = 7.04 kg * 19.6 m/s²
Force ≈ 137.664 Newtons

Therefore, the force of impact on the soles of your feet at the time of impact was approximately 137.664 Newtons.