Two horizontal forces act on a wagon, 550N forward and 300N backwards. What force is need to produce a net force of zero?

500 N 300N
-----> Object <--------
-----> <--------

Fnet=F1+F2+F3
0=500N-300N im so totally lost

If the unknown force is x, then you just need to solve

550 - 300 + x = 0

because the sum of all the forces needs to be zero. I think that once you get your answer you will
(a) see why the given formula works
(b) notice the typo as written

To find the force needed to produce a net force of zero, we need to balance the two horizontal forces acting on the wagon.

The first force is 550N, directed forward (to the right).
The second force is 300N, directed backwards (to the left).

Since these forces have opposite directions, we need to subtract the smaller force from the larger force to find the net force.

Net force = 550N - 300N

Subtracting the two forces, we get:

Net force = 250N

Therefore, a force of 250N in the opposite direction is needed to produce a net force of zero.

To find the force needed to produce a net force of zero, we need to consider the two horizontal forces acting on the wagon. The first force is 550N acting forward, and the second force is 300N acting backward.

When two forces act in opposite directions, we subtract them to find the net force. In this case, we'll subtract the backward force from the forward force:

Net force = Forward force - Backward force

Net force = 550N - 300N

Now, we can calculate the net force:

Net force = 250N

Therefore, a force of 250N in the opposite direction is needed to produce a net force of zero.