A positive charge of 0.0001258 C experiences

a force of 0.3 N when located at a certain
point.
What is the electric field magnitude at that
point?
Answer in units of N/C.

log1519

To find the electric field magnitude at a certain point, you can use Coulomb's law. Coulomb's law states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Coulomb's law is written as:

F = k * (q1 * q2) / r^2

where F is the force between the charges, k is the electrostatic constant (9 * 10^9 N m^2/C^2), q1 and q2 are the charges, and r is the distance between them.

In this case, we are given the force (F) and the charge (q1) and need to find the electric field magnitude (E) at the point where the charge is located. The electric field is defined as the force per unit charge, so we can use the equation:

E = F / q1

Let's substitute the given values into this equation:

E = 0.3 N / 0.0001258 C

Now we can calculate the electric field magnitude:

E = 2387.26 N/C

Therefore, the electric field magnitude at the given point is approximately 2387.26 N/C.