Calculate the expansion work done when 50g of water is electrolysis under constant pressure
-10kJ because you have to consider the work due the H2 (-6,7kJ) and the work due the O2 produced (-3.3kJ) in the reaction.
-10kj
-6887.6500kj
To calculate the expansion work done during the electrolysis of water, we need to know the change in volume of the system. The expansion work can be calculated using the equation:
Work = -PΔV
Where:
- Work is the expansion work done (in joules, J)
- P is the constant pressure (in pascals, Pa)
- ΔV is the change in volume of the system (in cubic meters, m^3)
However, in this case, we are given the mass of water instead of the change in volume. To find the change in volume, we need to use the density of water and the mass given.
The density of water at room temperature is around 1 gram per cubic centimeter (g/cm^3) or 1000 kilograms per cubic meter (kg/m^3).
In this case, we are given that 50g of water is undergoing electrolysis. So, using the density of water, we can calculate the change in volume:
Change in volume = Mass / Density
= 50g / 1000 kg/m^3
= 0.05 kg / 1000 kg/m^3
= 0.00005 m^3
Now that we have the change in volume, we can calculate the expansion work. However, we still need to know the value of the constant pressure (P) to proceed with the calculation.