A jeepney slows down from 10 m/s to 4 m/s in 6 s. What is the distance covered?
x = .5(vo+v)t
42
salamat sa lahat
To find the distance covered by the jeepney, we can use the formula:
distance = initial velocity × time + 0.5 × acceleration × time^2
In this case, the initial velocity (u) is 10 m/s, the final velocity (v) is 4 m/s, and the time (t) is 6 s.
To find the acceleration (a), we can use the formula:
acceleration = (final velocity - initial velocity) / time
Substituting the given values:
acceleration = (4 m/s - 10 m/s) / 6 s
acceleration = -6 m/s / 6 s
acceleration = -1 m/s^2
Now, we can substitute the values of u, v, a, and t into the distance formula:
distance = (10 m/s × 6 s) + 0.5 × (-1 m/s^2) × (6 s)^2
distance = 60 m + 0.5 × (-1 m/s^2) × 36 s^2
distance = 60 m - 0.5 m/s^2 × 36 s^2
distance = 60 m - 18 m
distance = 42 m
Therefore, the distance covered by the jeepney is 42 meters.