A metal tank contains three gases: oxygen, helium, and nitrogen. If the partial pressu of the three gases in the tank are 5 atm of O2, 900 mm Hg of N2, and 1.4 kPa of He what total pressure inside of the tank?
To find the total pressure inside the tank, you need to convert all the partial pressures to a common unit and then add them together.
First, let's convert the pressures:
1 atm = 760 mm Hg (approximately)
1 atm = 101.325 kPa
So, the given partial pressures can be converted as follows:
5 atm of O2 = 5 * 760 mm Hg ≈ 3800 mm Hg (approx.)
900 mm Hg of N2 = 900 mm Hg
1.4 kPa of He = 1.4 kPa
Now, we can add all the pressures together:
Total pressure = 3800 mm Hg + 900 mm Hg + 1.4 kPa
But we need to convert kPa to mm Hg because the other two pressures are already in mm Hg.
1 kPa = 7.5 mm Hg (approximately)
Therefore, we can convert kPa to mm Hg as follows:
1.4 kPa = 1.4 * 7.5 mm Hg = 10.5 mm Hg
Now, we can add all the pressures together:
Total pressure = 3800 mm Hg + 900 mm Hg + 10.5 mm Hg
Finally, calculating the total pressure gives us:
Total pressure = 4710.5 mm Hg
So, the total pressure inside the tank is approximately 4710.5 mm Hg.