A 112 g hockey puck glides across a frictionless ice surface with no horizontal forces acting on it. If the puck's velocity is 22.5 m/s to the right at t = 0 s, what will the puck's horizontal velocity be at t = 225 ms? Round your answer to the nearest 0.1 m/s.
No forces, no friction, no change in velocity. It will stay 22.5 forever.
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To find the puck's horizontal velocity, we can use the principle of conservation of momentum. Since there are no horizontal forces acting on the puck, its momentum in the horizontal direction remains constant.
The momentum (p) of an object is defined as the product of its mass (m) and velocity (v): p = m * v.
Given that the mass of the hockey puck is 112 g (or 0.112 kg) and its initial velocity is 22.5 m/s, we can calculate its initial momentum.
Initial momentum = mass * initial velocity = 0.112 kg * 22.5 m/s = 2.52 kg·m/s.
Since the momentum is conserved, the final momentum of the puck at t = 225 ms will be the same as the initial momentum.
To find the final velocity, we need to solve for the velocity with the given momentum and mass.
Final momentum = mass * final velocity
2.52 kg·m/s = 0.112 kg * final velocity.
Solving for the final velocity:
final velocity = 2.52 kg·m/s / 0.112 kg = 22.5 m/s.
Therefore, the puck's horizontal velocity at t = 225 ms will still be 22.5 m/s to the right.