H(t)=16t^+192t+2560 describe the height in feet, of the rock t seconds after thrown. What is the height of the rock in feet, 8 seconds after through?

To find the height of the rock in feet, 8 seconds after it was thrown, we need to substitute t = 8 into the equation H(t) = 16t^2 + 192t + 2560 and evaluate the expression.

H(t) = 16t^2 + 192t + 2560

Substituting t = 8:

H(8) = 16(8)^2 + 192(8) + 2560

Simplifying:

H(8) = 16(64) + 1536 + 2560

H(8) = 1024 + 1536 + 2560

H(8) = 5120 + 2560

H(8) = 7680

Therefore, the height of the rock, 8 seconds after it was thrown, is 7,680 feet.

just substitute 8 for each of the t's and add up the numbers.