factorize completely: a+b-bc-ac

Factor out the GCF:

-(b+a)(c-1)

thanks very much God bless you

a+b-bc-ac

= a - ac + b - bc
= a(1 - c) + b(1 - c)
= (a+b)(1-c)

looks prettier

To factorize the expression completely, we need to look for common factors or any patterns that might help simplify the expression. Let's break down the given expression and see what we can find:

a + b - bc - ac

First, notice that factorization involves grouping terms that have common factors. In this case, we can group the terms as follows:

a + b - (bc + ac)

Now, we can look for common factors within the parentheses:

a + b - c(b + a)

Within the parentheses, we have (b + a), which is the same as (a + b). We can rewrite the expression as:

a + b - c(a + b)

Factoring out the common factor (a + b), we get:

(a + b)(1 - c)

So, the completely factorized form of the given expression is: (a + b)(1 - c).