I'm preparing for a test. Can anyone check my answer for all these questions? These are my questions:
1. A stationary curling stone is struck in a glancing collision by a second curling stone of equal mass. If the first stone moves away at a velocity of 0.92 m/s [N71oW] and the second stone moves away at a velocity of 1.25 m/s [N44oE], what was the initial velocity of the second stone? (5 marks)
2. A billiard ball (0.62 kg) with a velocity of 2.0 m/s [N] hits another ball and has a velocity of 1.7 m/s [E] after the collision. Determine the impulse on the ball and the average force exerted on it during the collision if the duration of the collision was 0.0072 s. (5 marks)
3. Two billiard balls of equal mass undergo a head on collision. The red ball is travelling at 2.1 m/s [right] and hits the blue ball travelling at 3.0 m/s [left]. If the speed of the red ball after the collision is 3.0 m/s [left], determine the velocity of the blue ball after the collision. (5 marks)
4. A car with a mass of 1800 kg is initially travelling with a velocity of 22 m/s [N] when it collides with a truck with a mass of 3200 kg traveling with a velocity of 14 m/s [E]. If the two vehicles become attached during the collision, determine their final velocity.
1) 1.20 m/s (West 89.9 degrees North)
2) 1.6275 (kg.m)/s (East 49.6 degrees South) and the force exerted is 226N (East 49.6 degrees South)
Physics - Am I correct? - JOHN CENA, Thursday, January 28, 2016 at 8:02pm
3) 2.1m/s (right)
call m = 1 since they are the same
Initial momentum N = V2n + 0
Initial momentum E = V2e + 0
final momentum N = 1.25cos44 + .92 cos 71
final momentum E =1.25sin44 -.92sin71
so
V2n = 1.25cos44 + .92 cos 71
V2e = 1.25sin44 -.92sin71
yep that's what I did for #1. I just didn't post my process for the answer.
are my other answers correct?
V2n = 1.20
V2e = -.00155
v = sqrt (1.2^2 + .00155^2)
or about 1.2
and about North
Yes, we agre
Hey I am not going to do all these. You have the idea