Tony had an equal number of cranberry bars and walnut bars. He gave away 66 cranberry bars. He then had 4 times as many walnut bars as cranberry bars left. How many bars did he have at first?
i believe he had 70 but don't quote me on that
Tony had an equal number of cranberry bars and walnut bars. He gave away 66 cranberry bars. He then had 4 times as many walnut bars as cranberry bars left. How many bars did he have at first?
To solve this problem, we can use algebraic equations.
Let's say Tony initially had x cranberry bars. As mentioned in the problem, he also had an equal number of walnut bars.
After giving away 66 cranberry bars, Tony was left with x - 66 cranberry bars. According to the problem, he had 4 times as many walnut bars as cranberry bars left. So, he had 4(x - 66) walnut bars.
Since Tony had an equal number of cranberry and walnut bars originally, the equation becomes:
x = 4(x - 66)
Now, let's solve for x:
x = 4x - 264
Rearranging the equation:
4x - x = 264
3x = 264
Dividing both sides by 3:
x = 264/3
x ≈ 88
So, Tony initially had 88 cranberry bars and an equal number of walnut bars. To find the total number of bars, we multiply by 2:
Total number of bars = 2 * 88 = 176
Therefore, Tony had 176 bars originally.