How much positive charge is in 0.8 kg of neon?
The atomic weight (20.1797 g) of neon contains
Avogadro’s number of atoms, with each
atom having 10 protons and 10 electrons. The
elemental charge is 1.602 × 10−19 C and Avogadro’s
number is 6.023 × 1023
.
Answer in units of C.
please help
10 protons * 1.6*10^-19 C per proton
= 16*10^-19 C per atom
16*10^-19 C/atom * 6*10^23 atoms/mol = 96*10^4 C/mol
96*10^4 C/mol * 1 mol/20.2 g = 4.75*10^4 C/gram
4.75*10^4 C/gram * 800 grams = 3801*10^4 = 3.8 *10^7 C
Luckily the neutral atoms have an equal number of electrons to cancel that out.
To calculate the amount of positive charge in 0.8 kg of neon, we need to know the number of neon atoms present in that mass.
1. Find the number of moles of neon in 0.8 kg:
The molar mass of neon (atomic weight) is given as 20.1797 g/mol.
To convert kg to g, multiply 0.8 kg by 1000: 0.8 kg = 800 g.
Then, divide the mass (800 g) by the molar mass (20.1797 g/mol) to get the number of moles: 800 g / 20.1797 g/mol = 39.66 mol.
2. Find the number of neon atoms:
Avogadro's number tells us that there are 6.023 × 10^23 particles (atoms, molecules, or ions) in 1 mole of any substance.
Multiply the number of moles (39.66 mol) by Avogadro's number to find the number of neon atoms: 39.66 mol x (6.023 × 10^23 particles/mol) = 2.387 × 10^25 neon atoms.
3. Find the total positive charge:
Each neon atom has 10 protons, and since protons have positive charge, we can say that each neon atom has a positive charge of 10 times the elemental charge.
The elemental charge is given as 1.602 × 10^-19 C.
Multiply the number of neon atoms (2.387 × 10^25 atoms) by the positive charge of one neon atom (10 protons x 1.602 × 10^-19 C/proton) to get the total positive charge:
2.387 × 10^25 atoms x (10 protons/atom) x (1.602 × 10^-19 C/proton) = 3.834 × 10^6 C.
Therefore, there is approximately 3.834 × 10^6 Coulombs (C) of positive charge in 0.8 kg of neon.