if 100g of calcium carbonate on heating produces 44g of carbon dioxide,how much calcium oxide will be formed?
conservation of mass:
100g>44g+?
well, then ? must be 100-44 g
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To determine the amount of calcium oxide formed, we need to first understand the stoichiometry of the reaction. The balanced chemical equation for the reaction between calcium carbonate (CaCO3) and heat to produce calcium oxide (CaO) and carbon dioxide (CO2) is:
CaCO3 → CaO + CO2
From the equation, we can see that the molar ratio between CaCO3 and CaO is 1:1. This means that for every 1 mole of CaCO3 that reacts, 1 mole of CaO is produced.
To calculate the amount of CaO formed, we can use the molar mass of CaCO3 to convert grams to moles. The molar mass of CaCO3 is 40.1 g/mol for calcium (Ca) + 12.0 g/mol for carbon (C) + (3 * 16.0 g/mol) for oxygen (O), giving a total molar mass of 100.1 g/mol.
Now, let's calculate the number of moles of CaCO3 from the given mass:
100 g CaCO3 * (1 mol/100.1 g) = 0.999 moles
Since the molar ratio between CaCO3 and CaO is 1:1, the number of moles of CaO formed will also be approximately 0.999 moles.
Finally, we can convert the moles of CaO to grams using its molar mass. The molar mass of CaO is 40.1 g/mol for calcium (Ca) + 16.0 g/mol for oxygen (O), giving a total molar mass of 56.1 g/mol.
0.999 moles CaO * (56.1 g/1 mol) = 55.9 g CaO
Therefore, approximately 55.9 grams of calcium oxide (CaO) will be formed when 100 grams of calcium carbonate (CaCO3) is heated.